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Clarify C# docs for operators performing xform_inv
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<description>
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Inversely transforms (multiplies) the [Vector3] by the given [Basis] matrix, under the assumption that the basis is orthonormal (i.e. rotation/reflection is fine, scaling/skew is not).
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[code]vector * basis[/code] is equivalent to [code]basis.transposed() * vector[/code]. See [method Basis.transposed].
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For transforming by inverse of a non-orthonormal basis [code]basis.inverse() * vector[/code] can be used instead. See [method Basis.inverse].
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For transforming by inverse of a non-orthonormal basis (e.g. with scaling) [code]basis.inverse() * vector[/code] can be used instead. See [method Basis.inverse].
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</description>
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</operator>
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<operator name="operator *">
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