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Fix logic errors in match-statement Array & Dictionary Patterns
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@@ -0,0 +1,43 @@
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func foo(x):
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match x:
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{"key1": "value1", "key2": "value2"}:
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print('{"key1": "value1", "key2": "value2"}')
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{"key1": "value1", "key2"}:
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print('{"key1": "value1", "key2"}')
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{"key1", "key2": "value2"}:
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print('{"key1", "key2": "value2"}')
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{"key1", "key2"}:
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print('{"key1", "key2"}')
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{"key1": "value1"}:
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print('{"key1": "value1"}')
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{"key1"}:
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print('{"key1"}')
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_:
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print("wildcard")
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func bar(x):
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match x:
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{0}:
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print("0")
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{1}:
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print("1")
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{2}:
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print("2")
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_:
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print("wildcard")
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func test():
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foo({"key1": "value1", "key2": "value2"})
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foo({"key1": "value1", "key2": ""})
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foo({"key1": "", "key2": "value2"})
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foo({"key1": "", "key2": ""})
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foo({"key1": "value1"})
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foo({"key1": ""})
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foo({"key1": "value1", "key2": "value2", "key3": "value3"})
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foo({"key1": "value1", "key3": ""})
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foo({"key2": "value2"})
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foo({"key3": ""})
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bar({0: "0"})
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bar({1: "1"})
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bar({2: "2"})
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bar({3: "3"})
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